2018-team4-modules-快速数论变换2(NTT)
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原文章内容如下:
{{{
#pragma GCC optimize(3)
#pragma GCC optimize("Ofast")
#pragma GCC optimize("inline")
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
bool Finish_read;
template<class T>inline void read(T &x){Finish_read=0;x=0;int f=1;char ch=getchar();while(!isdigit(ch)){if(ch=='-')f=-1;if(ch==EOF)return;ch=getchar();}while(isdigit(ch))x=x*10+ch-'0',ch=getchar();x*=f;Finish_read=1;}
template<class T>inline void print(T x){if(x/10!=0)print(x/10);putchar(x%10+'0');}
template<class T>inline void writeln(T x){if(x<0)putchar('-');x=abs(x);print(x);putchar('\n');}
template<class T>inline void write(T x){if(x<0)putchar('-');x=abs(x);print(x);}
/*================Header Template==============*/
const int maxn=100005,fmaxn=19,Fmaxn=(1<<fmaxn);
const ll mod=998244353;
namespace {
inline ll Pow(ll a,ll b) {
ll res=1;
while(b) {
if(b&1)
res=res*a%mod;
a=a*a%mod;
b>>=1;
}
return res;
}
inline ll Inv(const ll &x) {
return Pow(x,mod-2);
}
inline ll Add(const ll &x,const ll &y) {
ll res=x+y;
if(res>=mod)
res-=mod;
return res;
}
inline ll Sub(const ll &x,const ll &y) {
ll res=x-y;
if(res<0)
res+=mod;
return res;
}
inline ll Mul(const ll &x,const ll &y) {
ll res=x*y;
if(res>=mod)
res%=mod;
return res;
}
inline ll Div(const ll &x,const ll &y) {
ll res=x*Inv(y);
if(res>=mod)
res%=mod;
return res;
}
}
namespace Transform {
const int G=3;
int mx=0,rev[Fmaxn],A[Fmaxn],B[Fmaxn],C[Fmaxn],W[fmaxn][Fmaxn];
inline void DFT(int *a,int n) {
if(mx<n) {
for(int i=mx;i<n;++i) {
int len=(1<<i);
ll w0=Pow(G,(mod-1)/(len<<1)),w=1;
for(int j=0;j<len;++j)
W[i][j]=w,w=Mul(w,w0);
}
mx=n;
}
rev[0]=0;
for(int i=1;i<(1<<n);++i) {
rev[i]=i&1?rev[i^1]|(1<<(n-1)):rev[i>>1]>>1;
if(i<rev[i])
swap(a[i],a[rev[i]]);
}
for(int l=0;l<n;++l) {
int len=(1<<l);
for(int i=0;i<(1<<n);i+=(len<<1)) {
for(int j=0;j<len;++j) {
int x=a[i+j],y=Mul(a[i+j+len],W[l][j]);
a[i+j]=Add(x,y),a[i+j+len]=Sub(x,y);
}
}
}
}
inline void IDFT(int *a,int n) {
reverse(a+1,a+(1<<n));
DFT(a,n);
ll invn=Inv((1<<n));
for(int i=0;i<(1<<n);++i)
a[i]=Mul(a[i],invn);
}
inline vector<int> FFT(vector<int> a,vector<int> b) {
int la=a.size()-1,lb=b.size()-1,lc=la+lb+1,lim=0;
while((1<<lim)<lc)
lim++;
vector<int>c;
c.resize(lc);
for(int i=0;i<(1<<lim);++i)
A[i]=B[i]=0;
for(int i=0;i<=la;++i)
A[i]=a[i];
for(int i=0;i<=lb;++i)
B[i]=b[i];
DFT(A,lim),DFT(B,lim);
for(int i=0;i<(1<<lim);++i)
A[i]=Mul(A[i],B[i]);
IDFT(A,lim);
for(int i=0;i<lc;++i)
if(A[i])
c[i]=A[i];
return c;
}
}
}}}
#pragma GCC optimize(3)
#pragma GCC optimize("Ofast")
#pragma GCC optimize("inline")
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
bool Finish_read;
template<class T>inline void read(T &x){Finish_read=0;x=0;int f=1;char ch=getchar();while(!isdigit(ch)){if(ch=='-')f=-1;if(ch==EOF)return;ch=getchar();}while(isdigit(ch))x=x*10+ch-'0',ch=getchar();x*=f;Finish_read=1;}
template<class T>inline void print(T x){if(x/10!=0)print(x/10);putchar(x%10+'0');}
template<class T>inline void writeln(T x){if(x<0)putchar('-');x=abs(x);print(x);putchar('\n');}
template<class T>inline void write(T x){if(x<0)putchar('-');x=abs(x);print(x);}
/*================Header Template==============*/
const int maxn=100005,fmaxn=19,Fmaxn=(1<<fmaxn);
const ll mod=998244353;
namespace {
inline ll Pow(ll a,ll b) {
ll res=1;
while(b) {
if(b&1)
res=res*a%mod;
a=a*a%mod;
b>>=1;
}
return res;
}
inline ll Inv(const ll &x) {
return Pow(x,mod-2);
}
inline ll Add(const ll &x,const ll &y) {
ll res=x+y;
if(res>=mod)
res-=mod;
return res;
}
inline ll Sub(const ll &x,const ll &y) {
ll res=x-y;
if(res<0)
res+=mod;
return res;
}
inline ll Mul(const ll &x,const ll &y) {
ll res=x*y;
if(res>=mod)
res%=mod;
return res;
}
inline ll Div(const ll &x,const ll &y) {
ll res=x*Inv(y);
if(res>=mod)
res%=mod;
return res;
}
}
namespace Transform {
const int G=3;
int mx=0,rev[Fmaxn],A[Fmaxn],B[Fmaxn],C[Fmaxn],W[fmaxn][Fmaxn];
inline void DFT(int *a,int n) {
if(mx<n) {
for(int i=mx;i<n;++i) {
int len=(1<<i);
ll w0=Pow(G,(mod-1)/(len<<1)),w=1;
for(int j=0;j<len;++j)
W[i][j]=w,w=Mul(w,w0);
}
mx=n;
}
rev[0]=0;
for(int i=1;i<(1<<n);++i) {
rev[i]=i&1?rev[i^1]|(1<<(n-1)):rev[i>>1]>>1;
if(i<rev[i])
swap(a[i],a[rev[i]]);
}
for(int l=0;l<n;++l) {
int len=(1<<l);
for(int i=0;i<(1<<n);i+=(len<<1)) {
for(int j=0;j<len;++j) {
int x=a[i+j],y=Mul(a[i+j+len],W[l][j]);
a[i+j]=Add(x,y),a[i+j+len]=Sub(x,y);
}
}
}
}
inline void IDFT(int *a,int n) {
reverse(a+1,a+(1<<n));
DFT(a,n);
ll invn=Inv((1<<n));
for(int i=0;i<(1<<n);++i)
a[i]=Mul(a[i],invn);
}
inline vector<int> FFT(vector<int> a,vector<int> b) {
int la=a.size()-1,lb=b.size()-1,lc=la+lb+1,lim=0;
while((1<<lim)<lc)
lim++;
vector<int>c;
c.resize(lc);
for(int i=0;i<(1<<lim);++i)
A[i]=B[i]=0;
for(int i=0;i<=la;++i)
A[i]=a[i];
for(int i=0;i<=lb;++i)
B[i]=b[i];
DFT(A,lim),DFT(B,lim);
for(int i=0;i<(1<<lim);++i)
A[i]=Mul(A[i],B[i]);
IDFT(A,lim);
for(int i=0;i<lc;++i)
if(A[i])
c[i]=A[i];
return c;
}
}