2016-C25-team1
从 Trac 迁移的文章
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原文章内容如下:
||Run ID||Time||Size||Problem||Language||Result||Failed test||
||166||4:56:44||5188||I||g++0x||Wrong answer||3||
||163||4:30:21||5139||I||g++0x||Wrong answer||3||
||158||3:12:17||3287||B||g++0x||OK||N/A||
||155||2:51:42||2448||C||g++0x||OK||N/A||
||153||2:40:44||1398||A||g++0x||OK||N/A||
||148||1:51:31||1456||A||g++0x||Wrong answer||3||
||147||1:46:09||1387||A||g++0x||Wrong answer||3||
||145||1:38:49||2143||E||g++0x||OK||N/A||
比赛链接: http://opentrains.snarknews.info/~ejudge/team.cgi?contest_id=001437
== 流水账 ==
== 总结 ==
== 题解 ==
=== A. BankCraft [sficiton] ===
多项式求逆。
http://picks.logdown.com/posts/189620-inverse-element-of-polynomial
=== J. Yet Another Binary Tree Problem [sfiction] ===
对所有子树单独做一遍 DP。设 f[i][mask] 为走到第 i 层,操作序列为 mask 是否必胜。i 从大到小转移。最底部的状态另外计算,cnt[i][mask] 表示从点 i 出发走到底,操作序列为 mask 所访问点数。
== 补题 ==
DFGHI ~~J~~
=== sfiction ===
* Unaccepted: J
| Run ID | Time | Size | Problem | Language | Result | Failed test |
| 166 | 4:56:44 | 5188 | I | g++0x | Wrong answer | 3 |
| 163 | 4:30:21 | 5139 | I | g++0x | Wrong answer | 3 |
| 158 | 3:12:17 | 3287 | B | g++0x | OK | N/A |
| 155 | 2:51:42 | 2448 | C | g++0x | OK | N/A |
| 153 | 2:40:44 | 1398 | A | g++0x | OK | N/A |
| 148 | 1:51:31 | 1456 | A | g++0x | Wrong answer | 3 |
| 147 | 1:46:09 | 1387 | A | g++0x | Wrong answer | 3 |
| 145 | 1:38:49 | 2143 | E | g++0x | OK | N/A |
比赛链接: http://opentrains.snarknews.info/~ejudge/team.cgi?contest_id=001437
流水账
总结
题解
A. BankCraft [sficiton]
多项式求逆。
http://picks.logdown.com/posts/189620-inverse-element-of-polynomial
J. Yet Another Binary Tree Problem [sfiction]
对所有子树单独做一遍 DP。设 f[i][mask] 为走到第 i 层,操作序列为 mask 是否必胜。i 从大到小转移。最底部的状态另外计算,cnt[i][mask] 表示从点 i 出发走到底,操作序列为 mask 所访问点数。
补题
DFGHI J
sfiction
- Unaccepted: J