ZOJ Problem Set - 3350
In the Bzu planet people use a calendar which is similar to ours. Maybe it is because Bzu planet has a similar "Sun" and "Moon". It is said this calendar was made by one of many kings in Bzu's history in thousands of years ago. In the legend, it says the king liked programming very much, and at one night he solved a very difficult problem. He was so happy that he wanted to make a new calendar to congratulate. Hence in his calendar, this very midnight with full moon is first second.
In this calendar, names of periods of time are same to ours, like days, months, years, minutes and seconds. In Bzu planet, the planet will reach same position on its revolution around the "Sun" every T1 seconds, the time between two neighbor full moons is T2 seconds and the time between two neighbor midnights is T3 seconds. It's very clear that a year is T1 seconds and a day is T3 seconds. And luckily, T1 is divisible by T3. So a leap year is unnecessary.
But T2 may be not divisible by T3, which is very troublesome. But our king was very clever, he made following rules.
Due to these complex rules, it is very difficult to calculate how many days in a month. Now many people in Bzu are turning to you for help.
There are multiple test cases. The first line of input contains an integer T (T<= 20), indicating the number of test cases. Then T test cases follow. There is a blank line between different test cases.
The first line of each test case contains 3 integers T1, T2 and T3 (1<=T3<=10000, 5<=T1/T3<=1000, T1 is divisible by T3, T3<T2<T1). The next line contains an integer Q (1<=Q<=100). Then Q lines follow, each line contains two integer Yi and Mi, means the Mith month in Yith year, (1 <= Yi <=5000, 0<= Mi <= 5000).
For each month, output how many days in that months. If there is no such month, output 0.
1 3650 295 10 4 1 1 1 2 2 0 2 13
29 30 18 0
Author: HUANG, Minzhi
Contest: ZOJ Monthly, June 2010