ZOJ Problem Set - 2846
One traveler travels among cities. He has to pay for this while he can get some incomes.
Now there are n cities, and the traveler has m days for traveling. Everyday he may go to another city or stay there and pay some money. When he come to a city ,he can get some money. Even when he stays in the city, he can also get the next day's income. All the incomes may change everyday. The traveler always start from city 1.
Now is your turn to find the best way for traveling to maximize the total income.
There are multiple cases.
The first line of one case is two positive integers, n and m .n is the number of cities, and m is the number of traveling days. There follows n lines, one line n integers. The j integer in the i line is the expense of traveling from city i to city j. If i equals to j it means the expense of staying in the city.
After an empty line there are m lines, one line has n integers. The j integer in the i line means the income from city j in the i day.
The input is finished with two zeros.
You must print one line for each case.It is the max income.
Hints:In the Sample ,the traveler can first go to city 2,then city 1,and finish his travel in city 1.
The total income is :
-1 + 4 - 2 + 4 - 1 + 4 = 8;
Author: Jia Li
Source: South Central China 2007 hosted by NUDT