
ZOJ Problem Set  2350
In the Blackjack card game, the player and the dealer are dealt two cards initially. One of dealer's cards is dealt face up and is known to the player but the other one is dealt face down. Given the two initial cards you are dealt and the dealer's faceup card, you are asked to compute the probability that your twocard hand is better than the dealer's twocard hand. This is not simple: the probability changes as the game is played because cards are dealt from the decks without replacement. To simplify the problem, we will only compute the probability when the cards are first dealt from the decks. That is, no cards have been dealt from the decks before. In this game, an Ace has a value of 1 or 11 (chosen by the person holding the cards), the face cards (K, Q, J) have a value of 10, and the values of the remaining cards are given by their numerical values. The player wins against the dealer if:
The value of an Ace is chosen to maximize the total value without exceeding 21. If we are only interested in twocard hands, it is impossible for the total value to exceed 21. Skilled players remember which cards have already been dealt and make decisions accordingly. To make this difficult, many casinos use multiple decks of cards to play the game. Each deck has 52 cards, 4 of each of A, K, Q, J, T (10), 9, ..., and 2. Input The input consists of a number of test cases. Each test case starts with a line containing a positive integer n (n <= 10) indicating the number of decks used. This is followed by a line containing 3 characters (separated by a space) in the set {A, K, Q, J, T, 9, ..., 2}, representing the dealer's faceup card and your two cards in the hand. In each case, assume that the n decks have been shuffled together randomly. The end of input is specified by n = 0. Output For each hand dealt, print on a line the probability of winning as a percentage, rounded to 3 decimal places. Separate the output of each case by a blank line. Sample Input
1 Sample Output
93.878% Source: Rocky Mountain 2004 