
ZOJ Problem Set  1771
Hermes Poseidon (HP) has produced a new calculator, the HP CXX, using the very latest in modern technology. It supports the four basic arithmetic operations on integer values from I to MMMMCMXCIX. In this problem, you are simulating The HP CXX. Each line of input will be either a roman numeral representation of a positive integer (between I(1) and MMMMCMXCIX(4999)), which will then be pushed to the top of the virtual stack, or it will be an arithmetic operation (+  * /) to be performed on the top two values of the stack. In addition, there is the = operation, which is a request to print the value of the top of the stack (in roman numerals, of course). For the  operation, subtract the first number on the stack from the second. For /, divide the second number on the stack by the first. An attempt to divide by 0 should result in the error message "division by zero exception". When that happens, push the dividend (nonzero number) back onto the stack, but not the divisor (zero). If an operation is requested, and there are insufficient numbers on the stack, print the error "stack underflow" and leave the stack unchanged. This applies to both the binary operations +*/ and the print operation =. If an attempt is made to print a number whose value is 0 or less, or whose value is greater than MMMMCMXCIX(4999), display the error message "out of range exception" and go on to the next line of input. Roman Numerals For those who are unfamiliar with Roman Numerals, here is a quick summary: Each letter used in Roman numerals stands for a different number: Roman Numeral Number A string of letters means that their values should be added together. For example, XXX = 10 + 10 + 10 = 30, and LXI = 50 + 10 + 1 = 61. If a smaller value is placed before a larger one, we subtract instead of adding. For instance, IV = 5  1 = 4 and XC = 100  10 = 90.
Each input line consists of either:
The input ends at the endoffile.
A line will be output:
 division by zero exception  stack underflow  out of range exception No other output should be produced
I
II 